(x^3-3x^2)/(2x^2+5)

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Solution for (x^3-3x^2)/(2x^2+5) equation: 


D( x )

2*x^2+5 = 0

2*x^2+5 = 0

2*x^2+5 = 0

2*x^2 = -5 // : 2

x^2 = -5/2

x in (-oo:+oo)

(x^3-(3*x^2))/(2*x^2+5) = 0

(x^3-3*x^2)/(2*x^2+5) = 0

x^3-3*x^2 = 0

x^2*(x-3) = 0

x-3 = 0 // + 3

x = 3

x^2*(x-3) = 0

(x^2*(x-3))/(2*x^2+5) = 0

( x-3 )

x-3 = 0 // + 3

x = 3

( x^2 )

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { 3, 0 }

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